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(8c^2)-30c+18=0
a = 8; b = -30; c = +18;
Δ = b2-4ac
Δ = -302-4·8·18
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-18}{2*8}=\frac{12}{16} =3/4 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+18}{2*8}=\frac{48}{16} =3 $
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